Math
posted by Bradley .
Hi, I needed help with this improper integral.
lower limit : 2
upper limit : infinity
integral of (lnx)/(x+1) dx
Thank You so much :D

I saw this question and have not been able to get a handle on it
we know that ln(x) has an expansion formula
http://upload.wikimedia.org/math/6/d/b/6dbf56b2e5f34d298c1e71ddd93b3448.png
but it only good for x1 < 1
so we could create a series of terms
= 1/(x+1) ( (x1)  (x1)^2 /2 + (x1)^3 / 3  .... )
but to integrate each term would be a mess
 even Wolfram, usually very dependable, could not handle it.
http://integrals.wolfram.com/index.jsp?expr=ln%28x%29%2F%28x%2B1%29&random=false
Respond to this Question
Similar Questions

calculus
1. integral oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? 
Calculus 2
If n is a positive integer, prove that integral[(lnx)^ndx=((1)^(n))*n!](lower limit=0, upper limit=1) Thanks Again, 
integral calculus..
Evaluate the following integral: çMvdv , with upper limit 'v' and lower limit 'u' 
integral calculus
Evaluate the following intergal: integral of [Mvdv] with upper limit 'v' and lower limit 'u' 
Definite Integral
Calculate the following integral: upper limit: 1 lower limit: 2 ∫ (5x + 3) / (x^2 + 4x + 7) dx Do I do a polynomial division for this one? 
math
Can someone help me answer this? If a < 5 the define integral [a, 4] 2.4e^(1.4x)dx = 44 Find the value a Define integral = integral sign a = lower limit 4 = upper limit 
math
Sorry I posted this question earlier with a error. Can anyone help me solve this now? 
math
Evaluate the following integral: Integral lower limit 0 and upper limit 2 of 3x(x7)dx 
CALCULUS II
Hi, I needed help with this improper integral. lower limit : 2 upper limit : infinity integral of (lnx)/(x+1) dx Thank You so much :D 
Math PLZ help me
Hi, I needed help with this improper integral. lower limit : 2 upper limit : infinity integral of (lnx)/(x+1) dx Thank You so much :D