The sum of two angles of a triangle is 116 degree and their differences is 24 degree.Find the measure of each angle of the triangle.
Let the angle ne x and y .
If we take x+y=116°....(1)
x-y=24°.....(2)
We know that the sum of an angle of an ∆ is 180°
So, x+y= 116°
x=(180-116)°
X=64°
Now , on adding (1)..(2)
We get, 2x=140
=>140/2
=>70°
Simply sum of am angle of an ∆ is 180°. So, another angle is 46°.
One angle is 70 , another is 46°, and third angle is 65°
let the angles be x and y
x+y = 116
x-y = 24
add them
2x = 140
x = 70
then y = 46
one angle is 70°, the other is 46° leaving 64° for the third angle
Science
To find the measure of each angle of the triangle, we can set up a system of equations based on the given information.
Let's denote the two angles as A and B, with A being the bigger angle. We are given that:
A + B = 116 (Equation 1)
A - B = 24 (Equation 2)
Now, we can solve this system of equations to find the values of A and B.
To do this, we can use the method of elimination. Add Equation 1 and Equation 2 together:
(A + B) + (A - B) = 116 + 24
Simplifying the equation, we get:
2A = 140
Now, divide both sides by 2 to solve for A:
A = 70
Substitute this value of A back into either Equation 1 or Equation 2. Let's use Equation 1:
70 + B = 116
Now, subtract 70 from both sides to solve for B:
B = 116 - 70
B = 46
So, the measure of angle A is 70 degrees and the measure of angle B is 46 degrees.