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The true highway mileage, Y, of a specific brand of hybrid vehicle has a normal distribution with a mean of 42 and a standard deviation of 1.5. Find the probability that a randomly selected hybrid vehicle gets more than 38 miles to the gallon.

  • statistics -

    μ=42
    σ=1.5
    so
    Z(38)=(38-μ)/σ
    Look up a normal distribution table for the probability of exceedingZ(38), which is the same as the probability of not exceeding -Z(38).

    Post your answer for checking if you wish.

  • statistics -

    .9961

  • statistics -

    .0039 or 39%

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