Post a New Question

General Physics 1

posted by .

1) A car moving with an initial velocity of 29.6 m/s decreases to a velocity of 17.9 m/s over a time
interval of 4.08 seconds.
(a.) What is the average acceleration of the car during this time?
(b.) Assuming the acceleration is constant, how far did the car travel during this time?

  • General Physics 1 -

    change in velocity/ change in time = (17.9-29.6) / 4.08
    = -2.67 m/s^2


    d = Vi t - (1/2) 2.67 * t^2
    = 29.6(4.08) - 1.33 (4.08^2)

    = 121 - 22.1
    = 98.9 m

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question