algebra
posted by zhandra .
computer manufacturing company would like to come up with a new laptop
computer such that its monitor is 80 a square inches smaller than the present ones.
Suppose the length of the monitor of the larger computer is 5 inches longer than
its width and the area of the smaller computer is 70 square inches. What are the
dimensions of the monitor of the larger computer?

If the larger monitor has width w, then its length is w+5. So, we have
w(w+5)80 = 70
w^2 + 5w  150 = 0
(w+15)(w10) = 0
...
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