A 0.020 rubber stopper is swung in a horizontal circle by 0.80 cm thread that makes 30.0 revolution every 20 seconds.
a.) what is the stopper's speed?
T=?
v=(2pi(r))/T
T=1.5 s?
T (period)
= time/rev
= 20 sec/ 30 rev
= 2/3 sec/rev
ω(angular speed)
=30 rev/20 seconds
=30/20 rev / sec
=30/20*2π radians / s
Velocity
=rω
=0.008m*ω m/s
To find the stopper's speed, we need to use the formula for the circumference of a circle:
C = 2πr
Here, "r" represents the radius of the circular motion, which is the length of the thread, given as 0.80 cm. So,
C = 2π(0.80 cm)
To find the stopper's speed, we need to divide the circumference by the time it takes for one revolution. The time for one revolution is found by taking the total time (20 seconds) and dividing it by the number of revolutions (30.0 revolutions).
T = 20 seconds / 30.0 revolutions
Now, we can substitute the values into the expression for speed:
v = (2πr) / T
v = (2π(0.80 cm)) / (20 seconds / 30.0 revolutions)
Let's calculate the speed.