what is the heat of reaction when 1 mole of gaseous hexane, c6h14 undergoes combustion as in following equation c6h14+19/2o2=6co2+7h2o a) -5221kj b)-38887kj c)-468.2kj d)+163.2KJ
b) -3887kj
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To determine the heat of reaction for the combustion of hexane (C6H14), we can use the equation given: C6H14 + 19/2O2 -> 6CO2 + 7H2O.
The coefficients in this balanced equation represent the moles of each substance involved in the reaction. In this case, it indicates that 1 mole of hexane reacts with 19/2 moles of oxygen (O2), producing 6 moles of carbon dioxide (CO2) and 7 moles of water (H2O).
The heat of reaction (also known as enthalpy change) is typically given in kilojoules (kJ) and indicates the amount of energy released or absorbed during a reaction. To find the heat of reaction, we need to refer to a thermochemical table or calculate it using the bond energies method.
However, in this case, the heat of reaction is already provided as answer choices. We can simply compare them to find the correct value.
The correct answer is (b) -38887 kJ, as it matches one of the given options.