calculus
posted by Anonymous .
A parabola ,f, intersect the x axis at A and B and the y axis at C. The axis of symmetry of the parabola has the equation x=3.The line through A and C has the equation g(x)=x+7. Determine the coordinates of A,B and C

(x+3)^2 = p (yq)
g = x + 7
when g = 0, x = A
0 = A + 7
A = 7
so A is 4 to the left of 3
therefore B is 4 to the right of 3 or at B = +1
so
g = 7 at x = 0 so C = 7
A = (7,0)
B = (1,0)
C = (0,7)
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