Post a New Question


posted by .

I posted this last night, A 0.500L vessel initially contains 0.0125 mol of H2S2 . Find the equilibrium concentrations of H2 and S2. Kc = 1.67 x 10^-7
2 H2S <--> 2 H2 + S2
I have come up with this equation so far, but I am lost now because I don’t even know if this is right.

1.67x10^-7 = ((4x^2)(x)) / (0.000625-4x^2)

  • Chemistry -

    It's close but not right.
    1.67E-7 = (2x)^2(x)/(0.025-2x)^2 is what you started with and that's correct. Your error was in expanding the denominator.
    1.67E-7 = 4x^3/(6.25E-4 -0.1x +4x^2)
    The next step is to multiply 1.67E-7 x the denominator, then collect the terms in descending order and you end up with a cubic equation. I haven't checked this but I ended up with (and you should go through the math to make sure it's right)
    4x^3 -6.68E-7x^2 +1.67E-8x -1/04E-10 = 0
    and solve that for x.

  • oops--Chemistry -

    I made a typo in that cubic equation.
    4x^3-6.68E-7x^2+1.67E-8x-1.04E-10 = 0

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question