Post a New Question

chemistry

posted by .

Calculate the pH of an aqueous solution
of 11.5 mg of KOH dissolved in 56 mL of
solution.

  • chemistry -

    mols KOH = grams/molar mass
    Then (KOH) = mols KOH/L solution
    Then (OH^-) = (KOH) since KOH is a strong electrolyte and dissociates completely.
    I would then do pOH = -log(OH^-) and follow with pH + pOH = pKw = 14 and solve for pH.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question