Determine the final velocity of a medicine ball that is dropped from a height of 7.00 meters. (assume air resistance is negligible)
I don't understand how to solve this with only change in x. I imagine I am supposed to assume initial velocity is 0 m/s, but, even if that is assumed, I don't understand what I can do to find the final velocity.
Yes, when an object is DROPPED, the
initial velocity is 0. When an object is
THROWN up or down, the initial velocity
is not 0.
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*7 = 137.2
V = 11.71 m/s.