i think its C.
A bag of fruit contains 4 apples,1 plum,2 apricots,and 3 oranges.Pieces of fruit are drawn twice
with replacement. What is P(apple,then apricot)?
A.4/5
B.2/25
C.3/25
D.3/5
4/10 * 2/10 = 2/25
To find the probability of drawing an apple and then an apricot from the bag, we need to consider two separate events happening one after the other:
1. The probability of drawing an apple
2. The probability of drawing an apricot
Let's calculate these probabilities separately and then multiply them together to get the final probability.
1. Probability of drawing an apple:
In the given bag, there are a total of 4 apples out of 4 + 1 + 2 + 3 = 10 fruits. So, the probability of drawing an apple on the first draw is 4/10.
2. Probability of drawing an apricot:
Since we are replacing the fruit after each draw, the total number of fruits remains the same for the second draw. Therefore, the probability of drawing an apricot on the second draw is 2/10.
Now, we need to multiply these probabilities to get the overall probability of drawing an apple and then an apricot:
P(apple, then apricot) = P(apple) * P(apricot) = (4/10) * (2/10) = 8/100 = 2/25
So, the correct answer is B) 2/25.