The eyes of a basket ball player are 6 feet above the floor. He is at the free-throw line, which is 15 feet from the center of the basket rim. The center of the rim is 10 feet above the floor

Determine the angle of elevation (to the nearest degree) from his eye to the center of the rim.

I used arcsin but it don't seem to be correct

Did you make a sketch?

I have a right-angled triangle with a base of 15 and a height of 4, (10 ft - his 6 ft)

so in relation to your angle of elevation Ø, we have the opposite and the adjacent, suggesting

tanØ = 4/15
arctan = 14.93°

So to the nearest degree: 15°

I did make a sketch, I just used the wrong function, thank you

To determine the angle of elevation from the basketball player's eye to the center of the rim, we can use trigonometry. The opposite side of the triangle is the height of the basket's center (10 feet), and the adjacent side is the horizontal distance from the free-throw line to the center of the rim (15 feet).

Let's use the tangent function to find the angle of elevation:

tan(angle) = opposite / adjacent

tan(angle) = 10 / 15

angle = arctan(10 / 15)

Using a calculator, the angle to the nearest degree is approximately 33 degrees.

Therefore, the angle of elevation from the basketball player's eye to the center of the rim is approximately 33 degrees.

To determine the angle of elevation from the basketball player's eye to the center of the rim, you can use trigonometry.

First, let's visualize the scenario:
- The basketball player's eye is 6 feet above the floor.
- The center of the rim is 10 feet above the floor.
- The distance from the free-throw line to the center of the rim is 15 feet.

Now, we can create a right triangle with the following dimensions:
- The vertical leg represents the height difference between the player's eye and the center of the rim, which is 10 - 6 = 4 feet.
- The horizontal leg represents the horizontal distance between the player and the center of the rim, which is 15 feet.

To find the angle of elevation, we need to use the tangent function:
tan(theta) = opposite / adjacent

In this case:
tan(theta) = 4 feet / 15 feet

To find theta, we can use the inverse tangent (arctan):
theta = arctan(4/15)

Calculating this on a calculator, you'll get an angle approximately equal to 14.48 degrees.

Therefore, the angle of elevation from the basketball player's eye to the center of the rim is approximately 14 degrees (to the nearest degree).