Help me with this please
A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit?
A. 0.38 A
B. 0.75 A
C. 1.35 A
D. 6.00 A
The equivalent resistance, R
=1/(1/10+1/20)=1/(3/20)=20/3 Ω
Use V=IR to find the current.
20/3= 6.666
9/6.666
c?
Correct!
thank you :)
Well, you see, electricity can be quite shocking sometimes! But don't worry, I'm here to lighten the mood and help you out.
To find the total current passing through the circuit, we'll need to use Ohm's Law, which states that V (voltage) equals I (current) times R (resistance). Ohm my, aren't we getting electrified already?
Since the two resistors are in parallel, the total resistance can be calculated using the formula:
1/Rt = 1/R1 + 1/R2
Let's plug in the values:
1/Rt = 1/10 + 1/20
Now, let's solve this equation:
1/Rt = 2/20 + 1/20
1/Rt = 3/20
To find Rt, we take the reciprocal of both sides:
Rt = 20/3
Now, we can find the total current (I) using Ohm's Law:
I = V/Rt
I = 9 / (20/3)
I = 27/20
I = 1.35 A
So, the answer is C. 1.35 A. It's quite a current affair, isn't it?
To find the total current passing through the circuit, we can use Ohm's Law and the concept of parallel resistors.
In a parallel circuit, the voltage across each resistor is the same, while the total current is the sum of the currents flowing through each resistor.
Let's break down the problem step by step:
Step 1: Find the equivalent resistance in the parallel combination of the 10.0 Ω resistor and the 20.0 Ω resistor.
The formula to calculate the equivalent resistance in a parallel combination of resistors is:
1/Req = 1/R1 + 1/R2 + ... + 1/Rn
where Req is the equivalent resistance, R1, R2, ..., Rn are the individual resistances.
So, in this case:
1/Req = 1/10.0 Ω + 1/20.0 Ω
To simplify this equation, we can find the least common denominator (LCD) and add the fractions:
LCD = 20.0 Ω
1/Req = (2/LCD) + (1/LCD)
1/Req = 3/LCD
Multiplying both sides by LCD, we get:
Req = LCD/3 = 20.0 Ω/3 = 6.67 Ω
Step 2: Calculate the total current passing through the circuit using Ohm's Law.
Ohm's Law states:
V = I * R
Where:
V is the voltage (9.00 V),
I is the current (to be determined),
R is the total resistance (6.67 Ω).
Rearranging the equation to solve for I:
I = V / R
Plugging in the values:
I = 9.00 V / 6.67 Ω
Calculating this expression, we find:
I ≈ 1.35 A.
Therefore, the total current passing through the circuit is approximately 1.35 A.
The correct answer is C. 1.35 A.