Liquid carbon disulfide reacts with 415 mL of

oxygen to produce the gases carbon dioxide
and sulfur dioxide. What volume of carbon
dioxide is produced?
Answer in units of L

This is a "simple" stoichiometry problem. Here is the format for solving all of these.

1. Write and balance the equation.
CS2 + 3O2 ==> CO2 + 2SO2

2. Convert what you have (in this case mL O2) to mols. The problem doesn't say it is a standard conditions but it must be. mols O2 = L/22.4 = about 0.0185

3. Using the coefficients in the balanced equation, convert mols O2 to mols of what you want (in this case CO2). That is done this way.
0.0185 mols O2 x (1 mol CO2/3 mols O2) = about 0.0062

4. Now convert mols CO2 to volume in L.
0.0062 mols CO2 x 22.4L/mol = about 0.14 L.

This 4-step procedure will do them all; print this out for future reference.
NOTE: Sometimes grams is given in the problem and not L. If that is done then mols = grams/molar mass
Sometimes the product is wanted in grams and not volume; in that case grams = mols x molar mass.

To find the volume of carbon dioxide produced, we first need to balance the chemical equation for the reaction between carbon disulfide (CS2) and oxygen (O2).

The balanced equation is:

CS2 + 3O2 → CO2 + 2SO2

According to the balanced equation, 1 mole of CS2 will react with 3 moles of O2 to produce 1 mole of CO2. We can use the stoichiometry of the balanced equation to calculate the volume of carbon dioxide produced.

1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, we need to convert the volume of oxygen given in the problem to moles, and then use the stoichiometric ratio to calculate the volume of carbon dioxide.

Given:
Amount of oxygen = 415 mL

To convert mL to L, we divide by 1000.
415 mL ÷ 1000 = 0.415 L

Next, we need to convert the volume of oxygen to moles using the ideal gas law. At STP, 1 mole of gas occupies 22.4 L.

PV = nRT

R (ideal gas constant) = 0.0821 L·atm/(mol·K)
T (temperature) = 273 K (STP)
P (pressure) = 1 atm (STP)

n = (PV) / (RT)
n = (1 atm * 0.415 L) / (0.0821 L·atm/(mol·K) * 273 K)
n ≈ 0.019 moles

According to the balanced equation, 1 mole of CS2 reacts to produce 1 mole of CO2. Therefore, the volume of CO2 produced will also be 0.019 L.

So, the volume of carbon dioxide produced is approximately 0.019 liters (L).