For their first 60 games the Robins had a record of 28 wins and 32 losses. How many of their next 90 games must they win if their total record is to show twice as many wins as losses?
The Robins need to win 100 games to have twice as many wins as losses.
They have 28 wins so they need 72 more wins.
Yes! Got it right.
Thanks as well.
You're welcome.
I hope you understand how I got the answer.
To solve this problem, we need to find the number of wins the Robins need in their next 90 games.
Given that the Robins had 28 wins in their first 60 games, we can calculate their number of losses in that same period: 60 - 28 = 32 losses.
We are asked to find the number of wins needed to have twice as many wins as losses in their total record. Let's denote the number of wins needed as 'x'.
To have twice as many wins as losses, the number of wins should be twice the number of losses. Therefore, we have the equation:
2*(32 + x) = 28 + x
Let's solve for x:
64 + 2x = 28 + x
Rearranging the equation:
2x - x = 28 - 64
x = -36
However, we cannot have a negative number of wins, so the answer is not valid.
This means that it is not possible for the Robins to have twice as many wins as losses in their total record, given their current record of 28 wins and 32 losses in their first 60 games.