A gas has a volume of V1 = 565 mL. If the
temperature is held constant, what volume
would the gas occupy if P2 = 16 P1?
Answer in units of mL
Use P1V1 = P2V2.
Since no "real" value is given for P1 you can assign any convenient number for P1, then 16 times that will be P2 and work the problem OR you can simply subsitute 16*P1 for P2.
To find the volume of the gas when the pressure is P2 = 16 P1, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure when the temperature is held constant. The equation for Boyle's Law is:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
In this case, the initial volume is given as V1 = 565 mL.
We are also given that P2 = 16 P1. We can substitute this value in the Boyle's Law equation:
P1 * V1 = (16 P1) * V2
Simplifying the equation, we divide both sides by P1:
V1 = 16 V2
Now we can solve for V2:
V2 = V1 / 16 = 565 mL / 16 = 35.31 mL
Therefore, the volume of the gas when the pressure is P2 = 16 P1 is 35.31 mL.