8.0g of mettalicoxide were reduced by hydrogen to give a metal of 2.0g. Calculate the mole of d metal that will combined with 0.5moles of oxygen.
This is done the same way as the last problem with Cu and Ag.
step 1. Write and balance the equation.
step 2. convert grams to mols.
step 3. convert mols of what you have to mols of what you want.
step 4. Not asked for in this problem but if needed, then grams = mols x molar mass.
2 grams of M in 8 grams of MOn
where M is metal symbol and n is O atoms per metal atom
There were 8-2 = 6 grams of O in MOn
6 grams of O * (1 mol of O/16 grams) = 6/16 = 3/8 mol of O which is 3/16 mol of O2
so 3/16 mol of O2 combines with 2 grams metal
so .5 mol of O2 combines with 16/3 or 5.33 grams of metal
To calculate the moles of metal that will combine with 0.5 moles of oxygen, we need to determine the molar ratio between the metal and oxygen using the given information.
First, we need to find the molar mass of the metal. Given that 8.0 grams of metallic oxide produced 2.0 grams of metal, we can calculate the molar mass of the metal using the equation:
Molar mass of metal = Mass of metal / Moles of metal
Molar mass of metal = 2.0 grams / Moles of metal
Next, we need to calculate the moles of the metal. Using the molar mass of the metal and the mass of the metal (2.0 grams), we can calculate the moles of the metal using the equation:
Moles of metal = Mass of metal / Molar mass of metal
Moles of metal = 2.0 grams / Molar mass of metal
Now, we have the moles of the metal that will combine with 0.5 moles of oxygen.