Maths
posted by Francis
find the equation of the perpendicular bisector of the line joining P(2, 4) to Q(5,1)
A. 8y14x 13=0
B. 8y14x13=0
C. 8y 14x13=0
D. 8y 14x 13=0
Please I need someone to help me with this, with an explanatory workings.

Steve
the bisector goes through the midpoint of PQ. That is (3/2,3/2)
PQ has slope 5/7, so the perpendicular has slope 7/5
Now you have a point and a slope, so the line is
y+3/2 = 7/5 (x+3/2)
10y + 15 = 14x + 21
10y14x6 = 0
I suspect a typo. If you graph the two lines, you will see that PQ is indeed bisected by the calculated line. 
Francis
So the question is wrong?

Steve
Yes. P and Q cannot be as given.
All of the choices have slope 7/4 or 7/4. 
Francis
ok, can you pls direct me on how to work a similar question?

Steve
Uh, geez  I believe I just did. Given two points, find the midpoint of the line connecting them.
Find the slope of that line, and take its negative reciprocal.
Now you have a point and a slope. Just write the equation of the bisecting line. 
Francis
Alright, thanks.

Francis
Sorry one more thing, how do you get the slope?
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