I don't want an answer I would just like to know what equations to use to answer the questions. It's confusing me. i. imgur. com/6CouaRj .png

An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion, as shown in this graph.


Answer the following questions:
a. What is the period and frequency of the pendulum’s motion?
b. How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
c. What is the acceleration due to gravity on the surface of the planet in m/s2? Determine the number of g-forces.
Show any necessary calculations.

thanks in advance

the period is 2 pi * square root of L/g

we know the length
however to find the period we need g
on the surface of earth g is about 9.81 m/s^3
HOWEVER on the moon for example is is only about one sixth of that so the period will be sqrt 6 longer
IN OTHER WORDS WE MUST KNOW g on this planet to find the period
frequency = 1/period

If you know the period, then of course you can find g
T = 2 pi sqrt (L/g local)
(T/2pi)^2 = L/g
g local = L /(T/2pi)^2

I can not see your graph of course but displacement and velocity are 90 degrees (pi/2) apart ad displacement and acceleration are 180 degrees (pi) apart
eg
if x = a sin wt
v = a w cos wt
(note cos wt=sin (wt+pi/2))
a = -a w^2 sin wt = -w^2 x
note sin (wt+pi) = -sin wt

To answer the questions, let's break down the information provided and identify the relevant equations to use:

a. To find the period (T) and frequency (f) of the pendulum's motion, we can use the equation:

T = 2π√(L/g)

where L is the length of the pendulum and g is the acceleration due to gravity.

b. To determine the phase difference between the displacements, velocity, and acceleration of the pendulum, we need to find the relationship between these quantities. For a simple harmonic motion (SHM) like a pendulum, the displacement, velocity, and acceleration can be related as follows:

x(t) = Acos(ωt + ø)
v(t) = -ωAsin(ωt + ø)
a(t) = -ω²Acos(ωt + ø)

where x(t) is the displacement at time t, v(t) is the velocity at time t, a(t) is the acceleration at time t, A is the amplitude of the motion, ω is the angular frequency (2πf), and ø is the phase angle.

c. To determine the acceleration due to gravity and the number of g-forces on the surface of the planet, we can use the relationship between the period of the pendulum and the acceleration due to gravity:

T = 2π√(L/g)

where T is the period of the pendulum, L is the length of the pendulum, and g is the acceleration due to gravity.

Using these equations, we can now proceed to answer the questions step by step.

To answer the questions about the pendulum's motion, we can use the following equations:

1. Period (T) and frequency (f):
The period (T) is the time taken for one complete oscillation, while the frequency (f) is the number of oscillations per unit time. They are inversely related, so we can use the equation:
T = 1 / f

2. Velocity (v):
The velocity of an object in simple harmonic motion can be calculated using the equation:
v = Aωcos(ωt + φ)

3. Acceleration (a):
The acceleration of an object in simple harmonic motion can be calculated using the equation:
a = -Aω^2sin(ωt + φ)

Where:
- A is the amplitude of the motion,
- ω (omega) is the angular frequency, given by ω = 2πf, where f is the frequency,
- t is the time, and
- φ (phi) is the phase constant, representing the initial conditions of the motion.

a. To find the period (T) and frequency (f) of the pendulum's motion:
The period can be determined from the time it takes for one complete oscillation, which can be read from the graph. Dividing 1 by the period will give the frequency.

b. To determine the phase delay between the displacements, velocities, and accelerations:
We need to calculate the phase constant (φ) for each case using the given information and equations. The phase delay is the time difference between the displacements and the velocities or accelerations.

c. To find the acceleration due to gravity on the planet's surface:
We can use the equation for the period of a simple pendulum:
T = 2π√(L / g)
Solving for g, we get:
g = (4π^2L) / T^2
To determine the number of g-forces, we divide the acceleration due to gravity on the planet's surface by the acceleration due to gravity on Earth, which is approximately 9.8 m/s^2.

Please note that in order to provide specific numerical answers, the graph you mentioned is required.