Silver forms a compound with nitrogen. In an experiment, 344.588 g of silver is placed in a reaction vessel with 15.906 of nitrogen. After the reaction is complete, all of the silver has been consumed, and there are 359.503 g of compound in the vessel. What is the mass of nitrogen left over (in grams)?
.........Ag + ....xN2 --> AgxNy
I......344.588.....0........0
add.............15.906.........
C.....-344.588.....-x......359.503
So you end up with 359.503
You started with...344.588
How much N2 was added?
Then N2 remaining = start-end = ?