Chemistry
posted by Anonymous .
What pressure (in atmospheres) will be exerted by 1.3 moles of gas in a 13 litre flask at 22 degrees Celcius? (Gas constant (R) = 0.0821 L atm K^1 mol^1)

Use ideal gas law:
PV=nRT (T in °K)
=>
P=nRT/V
=1.3 mol *0.0821 L atm °K^{1} mol^{1} *(22+273.16)°K/13 L
=2.423 atm
=2.4 atm (approx.)
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