y=1/3|x|-2 use integer values of x from-3 to 3 to graph the equation.
Please help me graph this
Thanks so much Toriel your answers are all right
just evaluate y for the given x's and plot the points
e.g , when x = -2
y = (1/3)(2) - 2
= 2/3 - 2
= -4/3 ------> so you have the point (-2, - 4/3
Answers:
1.) A
2.) D
3.) D
4.) D
5.) B
6.) D
7.) D
(yes, i know it may seem like a lot of "D's", but I promise you these are correct)
Thanks toriel you're the man
To graph the equation y = 1/3|x| - 2 using integer values of x from -3 to 3, you can follow these steps:
1. Plot the points:
- Set x = -3 and solve the equation to find y:
y = 1/3|-3| - 2 = 1 - 2 = -1
So the first point is (-3, -1).
- Repeat this step for x = -2, -1, 0, 1, 2, and 3 to get the following points:
(-2, -2/3), (-1, -5/3), (0, -2), (1, -1/3), (2, 4/3), (3, 5/3).
2. Draw line segments between the plotted points:
- Connect the points with a smooth curve or straight line, which will represent the graph of the equation.
The resulting graph should be a V-shaped curve with a vertex at (0, -2) and lines extending from the vertex towards the points on the x-axis.
Here is the graph of the equation y = 1/3|x| - 2 using integer values of x from -3 to 3:
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-3 -2 -1 0 1 2 3