What is the smallest value for x where y = sin 2x reaches its maximum ...wtf that means.
Steve, let's take this up a notch.
My number is 800 828 2950
I'll send you my email?
You are in the U.S. i take it?
I'm here in Lorain county OH.
i can send you a joinme link then you can see inside my pc while we talk on the phone together ...?
We can do some equations in real time with audio guidance ....?
let's do some equations together in real time while on our headsets together?
email is joseph
@SmartHealthInsuranceDOTcom
sin(2x) is always between -1 and 1.
Since sin(pi/2) is the first time that it reaches 1,
sin(2x)=1 when 2x = pi/2
That is, when x = pi/4
If you don't know wtf, just take a look at the graph and see where it reaches its maximum.
What graph ...?
Ok, so the quadratic 4 quadrant graph...?
i appreciate the help but I can't see it ...
Hmmm. I think what we have here is a failure to communicate...
The graph of sin(2x) is here. You can plainly see that it reaches its maximum at x = pi/4.
http://www.wolframalpha.com/input/?i=sin%282x%29
Not sure what quadratic you are referring to. If you instead meant sin^2(x), then that is a max at x = pi/2, since sin(pi/2) = 1. Now, sin(3pi/2) is -1, so sin^2(x) is also 1 there, but pi/2 comes first.
http://www.wolframalpha.com/input/?i=sin^2%28x%29
I just meant a 4 quad graph ...x and y intersecting like you have in the link.
OK, this part is a trig rule?
sin(2x) is always between -1 and 1.
Because it covers 2 integers? One on either side of 0 (origin?)On the x axis?
In this equation, they show no graph.
If that matters. How would i know that the graph runs in units of .5p (x axis) or .5p up and down the y axis?
Looking at the graph, I see where sin(pi/2) = 1.
I can see here that you are dividing each side by 2 and that's how we end up with p/4.
Can you put it in a proper equation form? I know this is tedious and ultra simplistic for you Steve, but for me it's like trying to read Egyptian hieroglyphics.
You can't imagine how much I want to understand this.
Thanks again.
hi guys XD
To find the smallest value for x where y = sin 2x reaches its maximum, we first need to understand what the function y = sin 2x represents.
The function y = sin 2x is an example of a sine function. In this particular case, the angle inside the sine function is given by 2x. The value of y depends on the value of 2x.
The sin function oscillates between -1 and 1, reaching its maximum value of 1 when the angle inside the function corresponds to a quarter of a complete cycle (π/2 radians or 90 degrees). Similarly, it reaches its minimum value of -1 at three-quarters of a complete cycle (3π/2 radians or 270 degrees).
So, if we equate 2x to π/2, we can solve for x:
2x = π/2
Divide both sides by 2:
x = π/4
Therefore, the smallest value for x where y = sin 2x reaches its maximum is x = π/4.
To verify this, you can graph the function y = sin 2x and observe that it reaches its maximum value at x = π/4. Additionally, you can input different values of x around π/4 and compare the corresponding y-values obtained from the function to confirm that y is indeed maximized at x = π/4.