find the exact x
log6^36 x= 2
log2^4 x= 2
log3^81 x= 4
Thank you for your help. I am trying.
6^x = 6^2
x = 2
2^x = 2^2
x = 2
3^x = 3^4
x = 4
ok
Thank you so much. Maybe I not as brain dead as I think. It is appreciated.
I think you have it down cold.
To find the exact value of x in each equation, we need to apply properties of logarithms.
1) log6^36 x = 2
In logarithmic form, this is equivalent to 6^(2) = x.
Solving this, we have x = 36.
2) log2^4 x = 2
In logarithmic form, this is equivalent to 2^(2) = x.
Solving this, we have x = 4.
3) log3^81 x = 4
In logarithmic form, this is equivalent to 3^(4) = x.
Solving this, we have x = 81.
So, the exact values of x for each equation are:
1) x = 36
2) x = 4
3) x = 81