if you dissolve 25.5 g of KBr in enough water to
make 1.75 L of solution, what is the molarity of the solution
.122
Molar mass of KBr = 118.99
Number of moles of KBr in soulution = 25.5/118.99= 0.124 moles
molarity = Moles of KBr /L solution = 0.214/1.75 =0.1222 M
Hope it will help you guys ! !
1 mole=119.00g
Solve for moles:
25.5g*(1 mole/119.00g)= moles of KBr
Molarity of KBr= moles of KBr/1.75L
Answer should contain 3-significant figures.
To find the molarity (M) of the solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
First, we need to convert the mass of KBr to moles. To do this, we need to know the molar mass of KBr. The molar mass of K (potassium) is 39.10 g/mol, and the molar mass of Br (bromine) is 79.90 g/mol.
The molar mass of KBr is:
Molar mass of KBr = (39.10 g/mol) + (79.90 g/mol) = 119.00 g/mol
Next, we can calculate the moles of KBr using the given mass:
Moles of KBr = mass of KBr / molar mass of KBr
Moles of KBr = 25.5 g / 119.00 g/mol
Now, we need to convert the volume of the solution from liters to moles. Since the molarity is defined as moles of solute per liter of solution, we can easily calculate it.
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (M) = moles of KBr / volume of solution
Given that the volume of the solution is 1.75 L, we can substitute the values:
Molarity (M) = (25.5 g / 119.00 g/mol) / 1.75 L
Calculate this expression to get the molarity of the solution.