Math
posted by Ara .
2. A rectangle whose perimeter is 80 m has an area of 384 m^2. Find the dimensions of the rectangle. Solve it as a polynomial.

If the width is w, we have
w(40w) = 384
w^2  40w + 384 = 0
since 384 = 4*96 or 8*48 or 12*32 or 16*24  aha!
(w16)(w24) = 0
Now you can easily figure the dimensions. Note that width is usually considered to be less than the length.
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