calculusanswer check
posted by Kim .
Determine the slope of the tangent line to the curve y=(x^2+3x)(x^22) at x=1.
I got 3 as my answer although I am not too sure that it's correct. I found the derivative of the function and then substituted 1 into the equation.

that's the proper method.
Using the product rule,
y' = (2x+3)(x^22) + (x^2+3x)(2x)
at x=1, that's (2+3)(12)+(13)(2) = 3 
I do not have the same value as yours.
Can you post the derivative? 
Oh, sorry, I had the two terms divided and not multiplied.

thanks!
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