If 59.4 pounds of alcohol are mixed with 28.3 pounds of water, what is the percent alcohol (by weight) in the mixture? Answer in units of %

To find the percent alcohol (by weight) in the mixture, we need to calculate the weight of alcohol and water separately, and then determine the ratio between them.

First, let's find the weight of alcohol in the mixture. Given that there are 59.4 pounds of alcohol, the weight of alcohol is 59.4 pounds.

Next, let's find the weight of water in the mixture. Given that there are 28.3 pounds of water, the weight of water is 28.3 pounds.

To find the percent alcohol (by weight), we need to divide the weight of alcohol by the total weight of the mixture (alcohol + water) and multiply by 100.

Total weight of the mixture = weight of alcohol + weight of water
Total weight of the mixture = 59.4 pounds + 28.3 pounds
Total weight of the mixture = 87.7 pounds

Percent alcohol (by weight) = (weight of alcohol / total weight of the mixture) * 100
Percent alcohol (by weight) = (59.4 pounds / 87.7 pounds) * 100
Percent alcohol (by weight) ≈ 67.7%

Therefore, the percent alcohol (by weight) in the mixture is approximately 67.7%.