The distance s in feet that a body falls in t seconds is given by the formula s=16t^2. If a body has been falling for 5 seconds, how far will it fall during the 6th second?
Please show work/explain
A. 16 ft.
B. 80 ft.
C. 176 ft.
D. 400 ft.
E. 576 ft.
To find how far a body will fall during the 6th second, we can substitute t = 6 into the formula for distance:
s = 16t^2
Substituting t = 6, we get:
s = 16(6)^2
s = 16(36)
s = 576 ft
Therefore, the body will fall 576 feet during the 6th second.
The correct answer is E. 576 ft.
that would be f(6)-f(5)
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