Consider an aqueous solution that contains
22 % (by mass) of a hypothetical solute Z.
The formula weight of the solute Z is 215.2.
The density of the solution is observed to be
1.12 g/mL. What is the molarity of Z in this
solution?
Answer in grams
22% w/w means 22 g solute Z in 100 g solution.
mols in 22 g = 22/215.2 = ?
Use density to convert 100 g to mL and convert to L.
Then M = mols/L
1.14
To find the molarity of solute Z in the solution, we need to determine the number of moles of Z in the solution first.
Step 1: Calculate the mass of solute Z in the solution.
The solution has a density of 1.12 g/mL, so for every milliliter of solution, it weighs 1.12 grams.
Since we have 22% by mass of solute Z, the mass of solute Z in the solution can be calculated as follows:
Mass of solute Z = (22/100) * (1.12 g/mL) = 0.2464 g/mL
Step 2: Convert the mass of solute Z to grams.
To calculate the mass of solute Z in grams, we need to know the volume of the solution. However, it is not provided in the given information. Hence, we cannot calculate the exact mass of solute Z in grams.
Therefore, we cannot calculate the molarity of Z in this solution without the volume of the solution.
Please provide the volume of the solution in milliliters (mL), and I'll be happy to help you further.