If two dice are rolled, what is the probability that a total is showing more than four

Pr(total>4)=1-pr(total<4)

the ways to get a total less than four are
1,1;1,2;1,3;2,1;3,1 or five ways.

Pr(total>4)=1- 5*(1/36)

Thank you so much.

To find the probability that a total is showing more than four when two dice are rolled, we need to determine the number of favorable outcomes (the outcomes we are interested in) and the total number of possible outcomes.

Step 1: Determine the number of favorable outcomes:
To find the number of favorable outcomes, we need to list all the possible combinations of two dice that result in a total greater than four. Let's list them:
- (3,2)
- (4,1)
- (4,2)
- (5,1)
- (5,2)
- (5,3)
- (6,1)
- (6,2)
- (6,3)
- (6,4)

Counting the number of combinations, we find that there are 10 favorable outcomes.

Step 2: Determine the total number of possible outcomes:
When two dice are rolled, each die has 6 faces, so the total number of possibilities for the first die is 6. Similarly, the total number of possibilities for the second die is also 6. Since the two dice are independent events, we can calculate the total number of possible outcomes by multiplying the number of possibilities for each die. Therefore, the total number of possible outcomes is 6 * 6 = 36.

Step 3: Calculate the probability:
To calculate the probability, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 10 / 36
Probability = 5 / 18

So, the probability that a total is showing more than four when two dice are rolled is 5/18 or approximately 0.278 or 27.8%.