If 2.03 g of helium gas occupies a volume of 12.0 L at 22°C, what volume will 6.19 g of helium gas occupy under the same conditions?

mols He = 2.03/molar mass He = n1

mols He = 6.19/molar mass He = n2

(n1/12L) = (n2/xL)
Solve for x L.