Physics
posted by Corey Brown .
A sniper fires a bullet at 120 m/s at 30° above the horizontal from the roof top of a 35 m high parking garage. If the bullet strikes the level ground beside the parking garage:
a) How long was the bullet in the air?
b) How far from the base of the parking garage did the bullet land?
c) At what angle did the bullet land?

Vo = 120m/s[30o]
Xo = 120*cos30 = 103.9 m/s.
Yo = 120*sin30 = 60 m/s.
a. Y = Yo * g*Tr = 0
Tr=Yo/g = 60/9.8 = 6.12 s. = Rise time.
h = ho + (Y^2Yo^2)/2g
h = 35 + (0(60^2))/19.6 = 218.7 m.
Above gnd.
h = 0.5g*t^2 = 218.7
4.9t^2 = 218.7
t^2 = 44.63
Tf = 6.68 s. = Fall time.
Tr+Tf = 6.12 + 6.68 = 12.8 s. = Time in
air.
b. d = Xo*(Tr+Tf) = 103.9m/s * 12.8s =
1330 m.
c. Y^2 = Yo^2 + 2g*h
Y^2 = 0 + 19.6*218.7 = 4286.52
Y = 65.5 m/s.
Tan A = Y/Xo = 65.5/103.9 = 0.63041
A = 32.2o 
TYPO: Change Y = Yo*g*Tr = 0 to
Y = Yo + g*Tr = 0 
Thanks Henry,
You're a good guy!
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