Chemistry

posted by Anonymous

How many litters of Oxygen will be required to burn 3.8 liters of propane, C3H8?

  1. Anonymous

    liters *

  2. DrBob222

    C2H8 + 5O2 ==> 2CO2 + 4H2O
    When working with gases we can use a shortcut in which we use L as if L = mols. Then we make the conversion form mols propane to mols O2 as usual.
    ?L O2 = 3.8 L C3H8 x (5 mols O2/1 mol C3H8) = 3.8 x 5 = ?

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