Chemistry

Question

posted by Anonymous Friday, May 2, 2014 at 1:53am.

How many litters of Oxygen will be required to burn 3.8 liters of propane, C3H8?

Chemistry - DrBob222 Friday, May 2, 2014 at 2:57pm
C2H8 + 5O2 ==> 2CO2 + 4H2O
When working with gases we can use a shortcut in which we use L as if L = mols. Then we make the conversion form mols propane to mols O2 as usual.
?L O2 = 3.8 L C3H8 x (5 mols O2/1 mol C3H8) = 3.8 x 5 = ?

Anonymous · Accepted Answer · 2014-05-02 06:19:47Z

Chemistry - Anonymous Friday, May 2, 2014 at 2:19am

liters *