A 0.63kg{\rm kg} mass vibrates according to the equation x=0.30cos7.00tx = 0.30 \cos 7.00 t, where xx is in meters and tt is in seconds.

Determine the amplitude.

The amplitude is given in the equation = .30

A 444g mass vibrates according to the equation x = 0.348 sin (5.82 t) where x is in meters and t is in seconds. Determine the total energy. Determine the kinetic energy when x is 14.0cm. Determine the potential energy when x is 14.0cm.

To determine the amplitude of the motion, we can refer to the equation x = Acos(ωt), where A represents the amplitude. In this equation, x is the displacement of the mass at a given time t, ω is the angular frequency, and A is the amplitude.

In the given equation x = 0.30cos(7.00t), we observe that the coefficient in front of the cosine function is 0.30. Therefore, the amplitude of the motion is A = 0.30 meters.

Hence, the amplitude of the mass's vibration is 0.30 meters.