math
posted by Robert
factorise 116(1y)^2
please help me

Reiny
difference of squares
= (1 + 4(1y) )(1 4(1y))
= (1 + 4  4y)(14 + 4y)
= (54y)(4y  3) 
Bobby
I am very good at maths, I am estimated to get an A+, but I hate turning point questions.
How do you find the turning point when given the quadratic function?
f(x)=(x+3)^2  16
Write down the coordinates of the turning point on the grap of y=f(x) 
Robert
given a GP below, find the values of m, and the next 2 terms:
m, m+3, m^2+3
Help me please 
Reiny
For a quadratic function , the turning point would be the vertex of the parabola.
since your equation is written in vertex form
f(x) = (x+3)^2  16
the vertex is (3,16) , which would be your turning point.
If your quadratic is written in the form
f(x) = ax^2 + bx + c
there is a quick way to find the vertex
the x of the vertex is b/(2a)
once you have that x, sub it into the equation to get the y
e.g.
y = 3x^2 + 9x  11
the x of the vertex is 9/6 = 3/2
then y = 3(9/4) + 9(3/2)  11
= 24/4  54/4  44/4
= 37/2
the vertex or turning point is (3/2 , 37/2) 
Reiny
if m , m+3, m^2 + 3 are in geometric progression, then
(m+3)/m = (m^2 + 3)/(m+3)
m^3 + 3m = m^2 + 6m + 9
m^3  m^2  3m  9 = 0
normally cubics are hard to solve, but I tried factors of 9
and found m = 3 to work
so the numbers are 3, 6, 12
so each number is double its previous one, r = 2
the next 2 numbers are 24 , 48
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