a plane leaves Vancouver headed for Toronto of a speed of 700 km/hr. Half an hour later a planes leaves toronto headed to vancouver travelling at a spped of 750 km/hr. the distance between vancouver and toronto is 3420 kn. How long after the plane leaves vancouver will it pass the other plane in the air?
let the time taken by the eastbound plane until they meet be t hrs
let the time taken by the westbound plane until they meet be t-1/2 hrs
distance covered by the easbound plane = 700t
distance covered by the westbound plane = 750(t - 1/2)
700t + 750(t-1/2) = 3420
700t + 750t - 375 = 3420
1450t = 3795
t = 2.617 hrs
= appr 2 hours and 37 minutes
To find out how long after the plane leaves Vancouver it will pass the other plane in the air, we need to calculate the time it takes for the two planes to meet.
Let's assume the time it takes for the plane leaving Vancouver to meet the other plane is t hours.
In half an hour, the plane leaving Vancouver would have already traveled for half an hour at a speed of 700 km/hr. So, it would have covered a distance of (700/2) km.
The plane leaving Toronto would be in the air for t hours at a speed of 750 km/hr. So, it would have traveled a distance of 750t km.
Given that the distance between Vancouver and Toronto is 3420 km, we can set up the following equation:
(700/2) + 750t = 3420
To solve for t, we can simplify the equation:
350 + 750t = 3420
750t = 3420 - 350
750t = 3070
t = 3070 / 750
t ≈ 4.09333
Therefore, it will take approximately 4.09333 hours (or about 4 hours and 5 minutes) after the plane leaves Vancouver for it to pass the other plane in the air.