A cylinder with a movable piston has the square meter 24cm2. How far will the piston go down if 5.0 kg weight is laid on the piston and the temperature remains the same?
P: 1.0 atm.
Help please :)
I do not know V, the initial Volume of gas so can not do the problemP V = n R T
P dV + V dP = 0 if n R and T do not change
P initial = 10^5 Newtons/m^2 ( or Pacals)
dV = (24*10^-4) x
V = I have no idea. You left this out.
dP = 5*9.81/(24*10^-4)
To calculate how far the piston will go down, we need to use the formula for pressure:
Pressure (P) = Force (F) / Area (A)
Here, we are given the pressure (P) as 1.0 atm.
To find the force (F), we can use the equation:
Force (F) = Mass (m) x Acceleration due to gravity (g)
Here, the mass (m) is given as 5.0 kg, and the acceleration due to gravity (g) is approximately 9.8 m/s².
Now, we need to find the area (A) of the piston. It is given that the piston has a square meter of 24 cm². To convert cm² to m², we divide by 10,000 since 1 m² = 10,000 cm². So, the area (A) can be calculated as:
Area (A) = 24 cm² / 10,000 = 0.0024 m²
Now, we have all the values we need to solve for the distance (d) the piston will go down. Rearranging the formula for pressure:
Force (F) = Pressure (P) x Area (A)
Substituting the given values:
F = 1.0 atm x 0.0024 m²
Now, we can substitute this force value into the equation for force:
F = 5.0 kg x 9.8 m/s²
Equating the two force values:
1.0 atm x 0.0024 m² = 5.0 kg x 9.8 m/s²
Now, we can solve for the distance (d):
d = (5.0 kg x 9.8 m/s²) / (1.0 atm x 0.0024 m²)
Calculating this, we find the distance (d) to which the piston will go down when a 5.0 kg weight is laid on it at a temperature that remains the same.