Deborah rolls two fair dice. What is the probability that the sum of the numbers rolled is 7?
total possible rolls: 36
rolls that make 7:
16 25 34 43 52 61
Looks like 6/36 to me
To find the probability that the sum of two fair dice rolls is 7, we first need to determine the total number of possible outcomes.
Each die has 6 faces numbered from 1 to 6, so the total possible outcomes for both dice combined is 6 * 6 = 36.
Next, we need to find the number of outcomes that result in a sum of 7. There are 6 possible combinations that result in a sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).
Therefore, the probability of rolling a sum of 7 is 6/36, which simplifies to 1/6.
So, the probability that the sum of the numbers rolled is 7 is 1/6.
To find the probability that the sum of the numbers rolled is 7, we first need to determine the number of favorable outcomes and the total number of possible outcomes.
The first die can show any number from 1 to 6, and similarly, the second die can also show any number from 1 to 6. So, the total number of possible outcomes is the product of the number of outcomes on each die, which is 6 * 6 = 36.
Now, let's determine the number of favorable outcomes, i.e., the outcomes where the sum of the numbers rolled is 7. There are six ways to roll a sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).
Therefore, the number of favorable outcomes is 6.
The probability is given by the number of favorable outcomes divided by the total number of possible outcomes. So, in this case, the probability is 6/36 = 1/6.
Thus, the probability that the sum of the numbers rolled is a 7 is 1/6.