1) what is the greates perimeter of a rectangle with an area of 39 square feet?

2) What is the least perimeter of a rectangle with an area of 32 square feet?

3) A rectangle has an area of 42 square inches. Which has a greater perimeter, the rectangle with the dimensions 21 x2 or the dimensions 6 x 7?

There is no such rectangle.

I can make the length some ridiculous length and the width very very small.
e.g. length = 5000
width = 39/5000= .0078
check: the area is 5000(.0078) = 39
Perimiter is 2(.0078) + 2(5000) = 1000.0156 ft

length = 20,000
width = 39/20000 = .00195
Perimeter = 40,000.0039

can you see the silliness of this question?

2. The least perimeter is obtained when your rectangle is a square.
then its side must be √32
and the perimieter is 4√32 or appr 22.6

3 Perimeter of the 21 by 2 is 2(21+2) = 46
perimeter of the 6 by 7 is 2(6+7) = 26
which is more ?

56

It is hard when you have a Kide in thrid grade

36 unit squares are joined to form a rectangle with least perimeter what is the perimeter of rectangle?

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1) To find the greatest perimeter of a rectangle with an area of 39 square feet, we need to find the dimensions that maximize the perimeter. The formula for the perimeter of a rectangle is P = 2L + 2W, where L is the length and W is the width.

To find the dimensions, we can start by listing the factors of 39:
1 x 39
3 x 13

From these factors, we can see that the possible dimensions for the rectangle are 1 x 39 or 3 x 13.

For a perimeter of 78, we can choose the dimensions 1 x 39 by substituting the values into the perimeter formula:
P = 2(1) + 2(39) = 2 + 78 = 80

Therefore, the greatest perimeter of a rectangle with an area of 39 square feet is 80 feet.

2) To find the least perimeter of a rectangle with an area of 32 square feet, we need to find the dimensions that minimize the perimeter. Using the same formula and method as in the previous question:

We can start by listing the factors of 32:
1 x 32
2 x 16
4 x 8

From these factors, we can see that the possible dimensions for the rectangle are 1 x 32, 2 x 16, or 4 x 8.

For a perimeter of 66, we can choose the dimensions 4 x 8 by substituting the values into the perimeter formula:
P = 2(4) + 2(8) = 8 + 16 = 24

Therefore, the least perimeter of a rectangle with an area of 32 square feet is 24 feet.

3) To compare the perimeters of two rectangles with different dimensions but the same area of 42 square inches, we can use the same perimeter formula and compare the values.

For the dimensions 21 x 2:
P = 2(21) + 2(2) = 42 + 4 = 46

For the dimensions 6 x 7:
P = 2(6) + 2(7) = 12 + 14 = 26

Therefore, the rectangle with the dimensions 21 x 2 has a greater perimeter than the rectangle with the dimensions 6 x 7.

I don't get that it is complicated

P= (2x8)+ (2x4) =24

21×2

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