calculate the vapor pressure of a solution 0.53 mol of cholestrol in 4.1 molof toluene at 32 degree C. pure toluene has a vapor pressure of 41 torr at 32 degree C
total mols = mols toluene + mols cholesterol
mol fraction toluene = X = mols toluene/total mols.
The ptoluene = Xtoluene * Potoluene
To calculate the vapor pressure of a solution, we can use Raoult's law. Raoult's law states that the vapor pressure of a solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent.
First, we need to calculate the mole fraction of the solvent (toluene) in the solution. The mole fraction (χ) can be calculated using the following formula:
χ(solvent) = moles of solvent / total moles of solution
Given:
moles of cholesterol (solute) = 0.53 mol
moles of toluene (solvent) = 4.1 mol
Total moles of solution = moles of cholesterol + moles of toluene
Let's calculate the mole fraction of toluene:
χ(solvent) = 4.1 mol / (0.53 mol + 4.1 mol) = 0.885
Now, we can use Raoult's law to calculate the vapor pressure of the solution:
vapor pressure of solution = χ(solvent) * vapor pressure of pure solvent
Given:
vapor pressure of pure toluene = 41 torr
vapor pressure of solution = 0.885 * 41 torr = 36.185 torr
Therefore, the vapor pressure of the solution is 36.185 torr.