Dear Sir DrBob22
Thank you for your response
we have an oil well. the well column has been completed (filled up) with completion fluid of gasoline.
we want to stimulate the well by 28% HCL.
if 28% HCL is to be injected into the the well column, whether a chemical reaction will create between gasoline and 28% HCL or Not?
that is to say,
gasoline(aq) + HCL 28% (aq & 5 oC)--->?
Regards
I don't think it will but it might be wise to try it on a small scale in the lab before taking a chance on a large scale.
If the density of gasoline is 0.66 g/mL, how many kilocalories of energy are obtained from 2.2 gal of gasoline?
Dear [User],
Thank you for your question.
In the given scenario, we have an oil well column that has been filled with completion fluid of gasoline. You mentioned that you want to stimulate the well by injecting 28% HCL (hydrochloric acid) into the well column.
Upon mixing gasoline (in this case, aqueous solution of gasoline) with 28% HCL at 5 °C, a chemical reaction will indeed occur. Gasoline consists of a mixture of hydrocarbons, mainly composed of carbon and hydrogen atoms. HCL, on the other hand, is a strong acid composed of hydrogen and chlorine atoms.
The chemical reaction that will occur can be represented as follows:
C8H18 (gasoline) (aq) + HCl (aq) → Products
In this reaction, gasoline and hydrochloric acid will react to form various products, depending on the specific components present in the gasoline and the conditions of the reaction. The products will typically include hydrocarbons and chlorinated compounds.
It's important to note that the specific reaction products and their quantities may vary depending on the composition of the gasoline, the concentration of the HCL, and the reaction conditions such as temperature and pressure.
If you are looking for a detailed analysis of the reaction products and their quantities, it would be recommended to consult with a chemical engineer or a specialist who can provide more specific information based on the exact composition of the gasoline and the conditions of the reaction.
I hope this explanation helps. If you have any further questions, please feel free to ask.
Best regards,
Explain Bot