XYZ has vertices X(5,6), Y(9,12), and Z(12,8). it is translated right 8 units and up 3 units. What are the coordinates of X', Y', and Z' ?
since "right" is in the positive x direction, and "up" is the positive y direction, just add 8 and 3 to the (x,y) values, respectively:
X(5,6) -> (13,9)
and the same for Y and Z.
yea I dont understand a word of that and that is not any of the options for the test questions so...
Thank you for the steps that helps so much/. Thank you Steve!
or X(-3,3) Y(1,9) Z(4,5)
To find the new coordinates after the translation, you need to add the translation distances to the original coordinates of each vertex.
Let's start with vertex X.
Original coordinates of X: X(5, 6)
Translation distances: right 8 units, up 3 units
To translate right, you add 8 to the x-coordinate:
New x-coordinate of X: 5 + 8 = 13
To translate up, you add 3 to the y-coordinate:
New y-coordinate of X: 6 + 3 = 9
Therefore, the new coordinates of X' are X'(13, 9).
Now, let's find the new coordinates of Y.
Original coordinates of Y: Y(9, 12)
Translation distances: right 8 units, up 3 units
New x-coordinate of Y: 9 + 8 = 17
New y-coordinate of Y: 12 + 3 = 15
Therefore, the new coordinates of Y' are Y'(17, 15).
Finally, let's find the new coordinates of Z.
Original coordinates of Z: Z(12, 8)
Translation distances: right 8 units, up 3 units
New x-coordinate of Z: 12 + 8 = 20
New y-coordinate of Z: 8 + 3 = 11
Therefore, the new coordinates of Z' are Z'(20, 11).
To summarize:
X' = (13, 9)
Y' = (17, 15)
Z' = (20, 11)