Question

Find the area of the region enclosed by these graphs and the vertical lines x = 0 and x = 3

f(x)=-x^2+2x+4 g(x)=-x+4

Answer 1

ʃ (-x^2+ 2x+ 4)-(-x+4)

ʃ (-x^2 +3x )dx

-x^3/3 + 3x^2/2 from 0 to 3
-(3)^3/3 +3(3)2/2 -0
-9 + 27/2
= 92