math (9)
posted by Vanessa .
Find the area of the region enclosed by these graphs and the vertical lines x = 0 and x = 3
f(x)=x^2+2x+4 g(x)=x+4

ʃ (x^2+ 2x+ 4)(x+4)
ʃ (x^2 +3x )dx
x^3/3 + 3x^2/2 from 0 to 3
(3)^3/3 +3(3)2/2 0
9 + 27/2
= 92
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