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Find the area of the region enclosed by these graphs and the vertical lines x = 3 and x = 5
f(x)=x^2+5 g(x)=1

  • math (8) -

    ʃ (x^2+5)-1)dx

    ʃ (x^2+4)dx

    x^3/3 + 4x from 3 to 5
    5^3/3 +4(5) -(3^3/3 + 4(3))
    125/3 +20 -27/3 -12
    =122/3

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