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x upper 2 - 10x+20=0
x=3, x=5
To solve the equation x^2 - 10x + 20 = 0, we can use the quadratic formula.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In our equation, the coefficients are:
a = 1
b = -10
c = 20
Substituting these values into the quadratic formula, we get:
x = (-(-10) ± √((-10)^2 - 4*1*20)) / (2*1)
Simplifying further:
x = (10 ± √(100 - 80)) / 2
x = (10 ± √20) / 2
x = (10 ± 2√5) / 2
x = 5 ± √5
Therefore, the solutions to the equation x^2 - 10x + 20 = 0 are:
x = 5 + √5
x = 5 - √5
Therefore, the answer is (5 + √5, 5 - √5).
To solve the quadratic equation x^2 - 10x + 20 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a, b, and c represent the coefficients of the quadratic equation. In our case, a = 1, b = -10, and c = 20.
Now, substituting these values into the formula, we get:
x = (-(−10) ± √((-10)^2 - 4(1)(20))) / (2(1))
x = (10 ± √(100 - 80)) / 2
x = (10 ± √20) / 2
x = (10 ± 2√5) / 2
x = (5 ± √5)
So, the solutions to the equation x^2 - 10x + 20 = 0 are x = 5 + √5 and x = 5 - √5.