Estimate the solubility of calcium fluoride, CaF2+, (a) in moles per liter and (b) in grams per liter of pure water.
CaF2+(s) = Ca2+(aq)+2f-(aq)
I have corrected the equation you wrote.
.......CaF2(s) = Ca2+(aq)+2F-(aq)
I......solid.....0.........0
C......solid.....x.........2x
E......solid.....x.........2x
Substitute the E line into the Ksp expression and solve for x = solubility in mols/L.
grams = mols in 1 L x molar mass
To estimate the solubility of calcium fluoride (CaF2) in moles per liter and grams per liter of pure water, we need to consider the balanced equation provided:
CaF2(s) ↔ Ca2+(aq) + 2F-(aq)
The solubility of a compound refers to the maximum amount of that compound that can dissolve in a particular solvent at a given temperature. In this case, we are interested in the solubility of calcium fluoride in water.
To estimate the solubility of CaF2, we can use the solubility product constant (Ksp) expression:
Ksp = [Ca2+][F-]^2
In the given equation, we have 1 mole of CaF2 producing 1 mole of Ca2+ and 2 moles of F-. Therefore, we can say that the concentration of Ca2+ in the solution is equal to the solubility of CaF2, and the concentration of F- in the solution is twice the solubility of CaF2.
(a) Solubility in moles per liter:
Hence, the solubility of CaF2 in moles per liter is equal to the concentration of Ca2+ ions and can be represented as [Ca2+]. This is also equal to the solubility of CaF2.
(b) Solubility in grams per liter:
To calculate the solubility of CaF2 in grams per liter, we need to convert the moles of CaF2 to grams. The molar mass of CaF2 is calculated as follows:
Molar mass of Ca = 40.08 g/mol
Molar mass of F = 18.99 g/mol
Therefore, the molar mass of CaF2 = (40.08 g/mol) + 2 * (18.99 g/mol) = 78.06 g/mol
Now, to convert the moles per liter of CaF2 to grams per liter, we simply need to multiply the solubility in moles per liter by the molar mass of CaF2.
I hope this helps!