what is the product of reaction K3(Al(C2O4)3).3H2O with KMnO4 in the present of NaOH?

2MnO4^- + 4H2O + 3C2O4^2- ==>6CO2 + 2MnO2 + 8OH^-

The reaction you mentioned involves the oxidation of a compound called K3(Al(C2O4)3).3H2O by KMnO4 in the presence of NaOH. The reaction is as follows:

K3(Al(C2O4)3).3H2O + KMnO4 + NaOH ->

To determine the product, let's analyze the reaction step by step.

Step 1: The KMnO4 in the presence of NaOH undergoes a redox reaction, where Mn(VII) is reduced to Mn(IV) in the form of MnO2.

2 KMnO4 + 3 NaOH -> K2MnO4 + 2 NaMnO4 + 2 H2O

Step 2: The K2MnO4, sodium manganate, reacts with the oxalate anion (C2O4^2-) in the K3(Al(C2O4)3).3H2O compound. This reaction produces insoluble manganese(IV) oxide (MnO2) and soluble carbonate ions (CO3^2-).

K2MnO4 + 3 C2O4^2- -> 2 MnO2 + 6 CO3^2-

Step 3: Finally, the formation of insoluble manganese(IV) oxide (MnO2) and soluble carbonate ions (CO3^2-) leads to the precipitation of solid manganese(IV) oxide.

2 MnO2 + 3 H2O -> Mn2O3 + 4 OH^-

Overall, the reaction can be summarized as:

K3(Al(C2O4)3).3H2O + 2 KMnO4 + 3 NaOH -> Mn2O3 + 3 H2O + 3 K2C2O4 + 2 NaMnO4

Therefore, the products are manganese(III) oxide (Mn2O3), water (H2O), potassium oxalate (K2C2O4), and sodium manganate (NaMnO4).

To determine the product of the reaction between K3(Al(C2O4)3)·3H2O and KMnO4 in the presence of NaOH, we need to consider the chemical equations and the reactions that occur between the compounds.

The presence of KMnO4 suggests that this compound acts as the oxidizing agent, while NaOH acts as a base, providing OH- ions.

Let's break down the reaction step-by-step:

1. First, identify the initial compounds:
- K3(Al(C2O4)3)·3H2O: This is the potassium salt of the complex ion [Al(C2O4)3]3-. It also contains three water molecules (H2O) as hydrates.
- KMnO4: This is potassium permanganate, an ionic compound with Mn7+ as the central metal ion.
- NaOH: This is sodium hydroxide, a strong base.

2. Consider the reaction between KMnO4 and NaOH:
- In alkaline conditions, KMnO4 can oxidize OH- ions to form MnO2(s) and water (H2O).

3. Identify the reaction between K3(Al(C2O4)3)·3H2O and KMnO4:
- The [Al(C2O4)3]3- complex ion can be oxidized by the MnO4- ion. The C2O4 ligand may be oxidized to CO2, while Al3+ may undergo hydrolysis to form hydroxyl complexes.

Overall, the products of the reaction could include MnO2(s) and various aluminum hydroxide complexes.

It is important to note that the exact products and stoichiometry may depend on the reaction conditions, such as the concentrations and temperature. Experimental verification or a reliable chemical reference should be consulted to confirm the specific products of this reaction.