A bullet of mass 100g is fired at avelocity 100m/s into a wooden block of mass 900g.If the bullet gets embeded into the block,then what would be the velocity of the system?
want answer
To calculate the velocity of the system after the bullet gets embedded in the block, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The formula to calculate momentum is:
momentum = mass × velocity
Let's calculate the initial momentum before the collision:
Initial momentum of the bullet = mass of the bullet × velocity of the bullet
= 100g × 100m/s
= 10,000 g m/s
Initial momentum of the block = mass of the block × 0 (assuming it is initially at rest)
= 900g × 0
= 0 g m/s
Total initial momentum = Initial momentum of the bullet + Initial momentum of the block
= 10,000 g m/s + 0 g m/s
= 10,000 g m/s
Now, let's calculate the final momentum after the collision:
Final momentum of the bullet (embedded in the block) = (mass of bullet + mass of block) × velocity of the system
The mass of the bullet is 100g, and the mass of the block is 900g, so:
Final momentum of the bullet (embedded in the block) = (100g + 900g) × velocity of the system
To find the velocity of the system, we need to divide the final momentum by the total mass:
velocity of the system = Final momentum / (mass of bullet + mass of block)
Substituting the values, we have:
velocity of the system = (10,000 g m/s) / (100g + 900g)
Simplifying further:
velocity of the system = (10,000 g m/s) / (1000g)
= 10 m/s
Therefore, the velocity of the system (wooden block with the embedded bullet) after the collision would be 10 m/s.